WebAug 13, 2024 · Given string str, the task is to find whether the given string is a palindrome or not using a stack. Examples: Input: str = “geeksforgeeks” Output: No Input: str = “madam” Output: Yes Recommended: Please try your approach on {IDE} first, before moving on to the solution. Approach: Find the length of the string say len. WebOct 1, 2024 · To check the palindrome number in Python, we may also use a function. and the string is referred to as a palindrome if its reverse contains the same string. In this example, we are not going to use the string function instead of that we will declare a variable and assign the string in which we want to check whether the string is palindrome or not.
Check if a string is palindrome in C using pointers
WebMar 2, 2024 · If the characters are not similar then the loop breaks and the string is not palindrome otherwise the string is a palindrome. In the case of symmetry, if the string length is even then the string is broken into two halves and the loop is run, checking the characters of the strings of both the half. WebDec 19, 2016 · I'm just getting started in python, and I'm trying to test a user-entered string as a palindrome. My code is: x=input ('Please insert a word') y=reversed (x) if x==y: print ('Is a palindrome') else: print ('Is not a palindrome') gold miners inn yelp
Number is Palindrome or not in Python PrepInsta
WebAug 15, 2024 · Palindrome Program using While Loop This is one of the easiest programs to find Palindrome program using while loop in Python Programming. Let’ dive into an … WebApr 3, 2024 · Python3 def palindrome (string): if(string == string [::-1]): return True else: return False def printSortedPalindromes (sentence): newlist = [] lis = list(sentence.split ()) for i in lis: if(palindrome (i)): newlist.append (i) newlist.sort () j = 0 for i in range(len(lis)): if(palindrome (lis [i])): lis [i] = newlist [j] j = j + 1 for i in lis: WebOct 13, 2008 · For any given number: n = num; rev = 0; while (num > 0) { dig = num % 10; rev = rev * 10 + dig; num = num / 10; } If n == rev then num is a palindrome: cout << "Number " << (n == rev ? "IS" : "IS NOT") << " a palindrome" << endl; Share Improve this answer Follow edited May 31, 2024 at 17:51 Deduplicator 44.3k 7 64 115 gold miners in usa